如图,已知ab∥cd∥ef ,gc⊥cf,角abc=65°,角EFC=40度,求角BCG的度数.
问答/405℃/2021-02-06 08:04:35
优质解答:
因为AB∥CD,∠ABC=∠BCD=65°,因为CD//EF,∠DCF=∠EFC=40°
又因为GC⊥CF,则∠GCF=90°
∠BCG=∠BCD-∠GCD=∠BCD-(∠GCF-∠DCF)=65°-(90°-40°)=65°-50°=15°
问答/405℃/2021-02-06 08:04:35
因为AB∥CD,∠ABC=∠BCD=65°,因为CD//EF,∠DCF=∠EFC=40°
又因为GC⊥CF,则∠GCF=90°
∠BCG=∠BCD-∠GCD=∠BCD-(∠GCF-∠DCF)=65°-(90°-40°)=65°-50°=15°