若x分之1+y分之1=2,则分式x-xy+y分之2x+3xy+2y的值是多少
问答/218℃/2024-07-05 22:32:33
优质解答：
1/x+1/y=2
则
(2x+3xy+2y)/(x-xy+y)
分子分母同除以xy
=(2/x+2/y+3)/(1/x+1/y-1)
=(4+3)/(2-1)
=7
问答/218℃/2024-07-05 22:32:33
1/x+1/y=2
则
(2x+3xy+2y)/(x-xy+y)
分子分母同除以xy
=(2/x+2/y+3)/(1/x+1/y-1)
=(4+3)/(2-1)
=7