已知 极限趋向于无穷大,函数X-1分之ax+5=6,则常数a=______________________.
问答/197℃/2025-01-16 06:59:17
优质解答：
ax+5=a(x-1)+5+a,
极限(ax+5)/(X-1)=极限[a(x-1)+5+a]/(X-1)=a+极限(5+a)/(X-1)=6
a+0=a=6
问答/197℃/2025-01-16 06:59:17
ax+5=a(x-1)+5+a,
极限(ax+5)/(X-1)=极限[a(x-1)+5+a]/(X-1)=a+极限(5+a)/(X-1)=6
a+0=a=6