两个质量均为5kg的铅球,相距1m时,他们之间的万有引力为多大
问答/407℃/2024-02-08 13:00:23
优质解答:
F=Gm1m2/r^2=6.67x10^-11N m^2/kg^2x5kgx5kg/1m^2=1.67x10^-9N
仅供参考!
2分钟内采纳系统会有额外分数奖励哦~
问答/407℃/2024-02-08 13:00:23
F=Gm1m2/r^2=6.67x10^-11N m^2/kg^2x5kgx5kg/1m^2=1.67x10^-9N
仅供参考!
2分钟内采纳系统会有额外分数奖励哦~